Problema com select JPA

Front-end
#1 
                try {
			EntityManagerFactory emf = null;
			EntityManager em = null;
			emf = Persistence.createEntityManagerFactory("Stlogin");
			em = emf.createEntityManager();
			Query query = em
					.createQuery("SELECT usuario, senha FROM Usuario WHERE usuario = :usuario and senha = :senha");
			query.setParameter("usuario", "123");
			query.setParameter("senha", "123");
			
			Usuario user = (Usuario) query.getSingleResult();
		
			System.out.println(user.getUsuario());
			System.out.println(user.getSenha());
		} catch (NoResultException e) {
			System.out.println(e.getMessage());
		} catch (NonUniqueResultException e) {
			System.out.println(e.getMessage());
		} catch (Exception e) {
			System.out.println(e.getMessage());
		}

Erro:

[EL Info]: 2011-02-24 13:14:13.626--ServerSession(809606405)--EclipseLink, version: Eclipse Persistence Services - 2.1.2.v20101206-r8635
[EL Info]: 2011-02-24 13:14:14.033--ServerSession(809606405)--file:/D:/Desenvolvimento/Java Web/SistemaLogin/build/classes/_Stlogin login successful
An exception occurred while creating a query in EntityManager: 
Exception Description: Syntax error parsing the query [SELECT usuario, senha FROM Usuario WHERE usuario = :usuario and senha = :senha], line 1, column 35: syntax error at [WHERE].
Internal Exception: MismatchedTokenException(79!=80)

Alguém sabe porque esse erro?

Obrigado.

#2

tenta assim:

"SELECT u FROM Usuario u WHERE u.usuario = :usuario and u.senha = :senha"
#3

ou então assim:


SELECT  Usuario.usuario, Usuario.senha 
FROM    Usuario 
WHERE  Usuario.usuario = :usuario 
AND      Usuario.senha = :senha
#4

Deu certo, obrigado :).

Mas porque isso? Por causa do EclipseLink?

#5